Soal Simulasi Ujian IPS Kelas 12
Tahun 2018Soal Pilihan Ganda
5. -2∫3 (4x2 - 4x + 1) dx = ...
A. 41 4/6
B. 33 3/6
C. 24 2/6
D. 10 1/6
E. 0
Jawaban : A
-2∫3 (4x2 - 4x + 1) dx
= [4/3 x3- 2x2 + x + C]-23
= 4/3.33- 2. 32 + 3 + C - (4/3. (-2)3 - 2 . (-2)2 + (-2) + C)
= 36 - 18 + 3 - (-32/3 - 8 - 2)
= 21 + 32/3 + 8 + 2
= 31 + 32/3
= 31 + 10 2/3
= 41 2/3
= 41 4/6
-2∫3 (4x2 - 4x + 1) dx
= [4/3 x3- 2x2 + x + C]-23
= 4/3.33- 2. 32 + 3 + C - (4/3. (-2)3 - 2 . (-2)2 + (-2) + C)
= 36 - 18 + 3 - (-32/3 - 8 - 2)
= 21 + 32/3 + 8 + 2
= 31 + 32/3
= 31 + 10 2/3
= 41 2/3
= 41 4/6
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