Soal Simulasi Ujian IPS Kelas 12
Tahun 2018Soal Pilihan Ganda
32. Akar-akar persamaan kuadrat x2 - 4x + 5 = 0 yaitu p dan q. Maka persamaan kuadrat yang akar-akarnya (3p+1) dan (3q+1) yaitu ...
A. x2 + 14x + 58 = 0
B. x2 - 14x + 58 = 0
C. x2 - 14x - 58 = 0
D. x2 - 10x + 34 = 0
E. x2 + 10x + 34 = 0
Jawaban : B
Persamaan x2 - 4x + 5 = 0
a = 1
b = -4
c = 5
sifat akar-akarnya :
p + q = - b /a
p + q = 4 / 1
p + q = 4
p . q = c / a
p . q = 5 / 1
p . q = 5
persamaan gres dengan akar-akar : (3p+1) dan (3q+1)
(3p+1) + (3q+1) = - B /A
3p + 3q + 2 = - B / A
3 (p + q) + 2 = - B/A
3 . 4 + 2 = -B/A
12 + 2 = - B/A
14 = - B/A
(3p+1) + (3q+1) = C/A
9pq + 3p + 3q + 1 = C/A
9pq + 3 (p + q) + 1 = C/A
9 . 5 + 3 . 4 + 1 = C/A
45 + 12 + 1 = C/A
58 = C/A
Jika A =1, B = -14, C = 58
persamaan yang gres : x2 - 14x + 58 = 0
Persamaan x2 - 4x + 5 = 0
a = 1
b = -4
c = 5
sifat akar-akarnya :
p + q = - b /a
p + q = 4 / 1
p + q = 4
p . q = c / a
p . q = 5 / 1
p . q = 5
persamaan gres dengan akar-akar : (3p+1) dan (3q+1)
(3p+1) + (3q+1) = - B /A
3p + 3q + 2 = - B / A
3 (p + q) + 2 = - B/A
3 . 4 + 2 = -B/A
12 + 2 = - B/A
14 = - B/A
(3p+1) + (3q+1) = C/A
9pq + 3p + 3q + 1 = C/A
9pq + 3 (p + q) + 1 = C/A
9 . 5 + 3 . 4 + 1 = C/A
45 + 12 + 1 = C/A
58 = C/A
Jika A =1, B = -14, C = 58
persamaan yang gres : x2 - 14x + 58 = 0
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