Soal Ujian Matematika IPA Kelas 12
Tahun 2017Soal Pilihan Ganda
8. Akar-akar persamaan kuadrat 3x2 - x - 4 = 0 yaitu x1 dan x2. Persamaan kuadrat gres yang akar-akarnya (3x1 - 1) dan (3x2 - 1) yaitu ..
A. x2 - x - 38 = 0
B. x2 + x - 32 = 0
C. x2 + x + 12 = 0
D. x2 + x - 12 = 0
E. x2 - x - 12 = 0
Jawaban : D
3x2 - x - 4 = 0
a = 3
b = -1
c = -4
sifat akar-akar persamaan :
x1 + x2 = - b /a
x1 + x2 = - (-1) /3
x1 + x2 = 1/3
x1 . x2 = c /a
x1 . x2 = -4 /3
sifat persamaan kuadrat gres :
(3x1 - 1) + (3x2 - 1) = - b/a
3x1+ 3x2 - 2 = - b/a
3 (x1 + x2) - 2 = - b/a
3 (1/3) - 2 = - b/a
3 - 2 = b/a
1 = b/a
(3x1 - 1) . (3x2 - 1) = c/a
9x1x2 - 3x1- 3x2 + 1 = c/a
9x1x2 - 3(x1 + x2) + 1 = c/a
9 (-4 /3) - 3 (1/3) + 1 = c/a
-12 - 1 + 1 = c/a
-12 = c /a
jikalau a = 1,
1 = b/a
b = 1
- 12 = c/a
- 12 = c/1
c = -12
persamaan ax2 + bx + c = 0
x2 + x - 12 = 0
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